3(2r-3)=r+2(4r-3)

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Solution for 3(2r-3)=r+2(4r-3) equation: 



3(2r-3)=r+2(4r-3)

We move all terms to the left:

3(2r-3)-(r+2(4r-3))=0

We multiply parentheses

6r-(r+2(4r-3))-9=0



We calculate terms in parentheses: -(r+2(4r-3)), so:

r+2(4r-3)

We multiply parentheses

r+8r-6

We add all the numbers together, and all the variables

9r-6

Back to the equation:

-(9r-6)



We get rid of parentheses

6r-9r+6-9=0

We add all the numbers together, and all the variables

-3r-3=0

We move all terms containing r to the left, all other terms to the right

-3r=3

r=3/-3

r=-1

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