3(2r-4)-2(r+4)=

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Solution for 3(2r-4)-2(r+4)= equation:


Simplifying
3(2r + -4) + -2(r + 4) = 0

Reorder the terms:
3(-4 + 2r) + -2(r + 4) = 0
(-4 * 3 + 2r * 3) + -2(r + 4) = 0
(-12 + 6r) + -2(r + 4) = 0

Reorder the terms:
-12 + 6r + -2(4 + r) = 0
-12 + 6r + (4 * -2 + r * -2) = 0
-12 + 6r + (-8 + -2r) = 0

Reorder the terms:
-12 + -8 + 6r + -2r = 0

Combine like terms: -12 + -8 = -20
-20 + 6r + -2r = 0

Combine like terms: 6r + -2r = 4r
-20 + 4r = 0

Solving
-20 + 4r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 4r = 0 + 20

Combine like terms: -20 + 20 = 0
0 + 4r = 0 + 20
4r = 0 + 20

Combine like terms: 0 + 20 = 20
4r = 20

Divide each side by '4'.
r = 5

Simplifying
r = 5

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