3(2r-5)=272r-5

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Solution for 3(2r-5)=272r-5 equation: 



3(2r-5)=272r-5

We move all terms to the left:

3(2r-5)-(272r-5)=0

We multiply parentheses

6r-(272r-5)-15=0

We get rid of parentheses

6r-272r+5-15=0

We add all the numbers together, and all the variables

-266r-10=0

We move all terms containing r to the left, all other terms to the right

-266r=10

r=10/-266

r=-5/133

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