3(2r-7)/7=(3r-12)/2

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Solution for 3(2r-7)/7=(3r-12)/2 equation: 


r in (-oo:+oo)

(3*(2*r-7))/7 = (3*r-12)/2 // - (3*r-12)/2

(3*(2*r-7))/7-((3*r-12)/2) = 0

(3*(2*r-7))/7+(-1*(3*r-12))/2 = 0

(2*3*(2*r-7))/(2*7)+(-1*7*(3*r-12))/(2*7) = 0

2*3*(2*r-7)-1*7*(3*r-12) = 0

42-9*r = 0

(42-9*r)/(2*7) = 0

(42-9*r)/(2*7) = 0 // * 2*7

42-9*r = 0

42-9*r = 0 // - 42

-9*r = -42 // : -9

r = -42/(-9)

r = 14/3

r = 14/3

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