3(2t+1)+7f=55

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Solution for 3(2t+1)+7f=55 equation:


Simplifying
3(2t + 1) + 7f = 55

Reorder the terms:
3(1 + 2t) + 7f = 55
(1 * 3 + 2t * 3) + 7f = 55
(3 + 6t) + 7f = 55

Reorder the terms:
3 + 7f + 6t = 55

Solving
3 + 7f + 6t = 55

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 7f + -3 + 6t = 55 + -3

Reorder the terms:
3 + -3 + 7f + 6t = 55 + -3

Combine like terms: 3 + -3 = 0
0 + 7f + 6t = 55 + -3
7f + 6t = 55 + -3

Combine like terms: 55 + -3 = 52
7f + 6t = 52

Add '-6t' to each side of the equation.
7f + 6t + -6t = 52 + -6t

Combine like terms: 6t + -6t = 0
7f + 0 = 52 + -6t
7f = 52 + -6t

Divide each side by '7'.
f = 7.428571429 + -0.8571428571t

Simplifying
f = 7.428571429 + -0.8571428571t

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