3(2t+1)-(t-2)-2(3t+4)=0

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Solution for 3(2t+1)-(t-2)-2(3t+4)=0 equation: 



3(2t+1)-(t-2)-2(3t+4)=0

We multiply parentheses

6t-(t-2)-6t+3-8=0

We get rid of parentheses

6t-t-6t+2+3-8=0

We add all the numbers together, and all the variables

-1t-3=0

We move all terms containing t to the left, all other terms to the right

-t=3

t=3/-1

t=-3

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