3(2t+1)-2(t-2)=5

Solution for 3(2t+1)-2(t-2)=5 equation:

Simplifying
3(2t + 1) + -2(t + -2) = 5

Reorder the terms:
3(1 + 2t) + -2(t + -2) = 5
(1 * 3 + 2t * 3) + -2(t + -2) = 5
(3 + 6t) + -2(t + -2) = 5

Reorder the terms:
3 + 6t + -2(-2 + t) = 5
3 + 6t + (-2 * -2 + t * -2) = 5
3 + 6t + (4 + -2t) = 5

Reorder the terms:
3 + 4 + 6t + -2t = 5

Combine like terms: 3 + 4 = 7
7 + 6t + -2t = 5

Combine like terms: 6t + -2t = 4t
7 + 4t = 5

Solving
7 + 4t = 5

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 4t = 5 + -7

Combine like terms: 7 + -7 = 0
0 + 4t = 5 + -7
4t = 5 + -7

Combine like terms: 5 + -7 = -2
4t = -2

Divide each side by '4'.
t = -0.5

Simplifying
t = -0.5