3(2t+1)-7=t-(t+3)

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Solution for 3(2t+1)-7=t-(t+3) equation: 



3(2t+1)-7=t-(t+3)

We move all terms to the left:

3(2t+1)-7-(t-(t+3))=0

We multiply parentheses

6t-(t-(t+3))+3-7=0



We calculate terms in parentheses: -(t-(t+3)), so:

t-(t+3)

We get rid of parentheses

t-t-3

We add all the numbers together, and all the variables

-3

Back to the equation:

-(-3)



We add all the numbers together, and all the variables

6t-1=0

We move all terms containing t to the left, all other terms to the right

6t=1

t=1/6

t=1/6

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