3(2t+1)-9=t-(t-5)

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Solution for 3(2t+1)-9=t-(t-5) equation: 



3(2t+1)-9=t-(t-5)

We move all terms to the left:

3(2t+1)-9-(t-(t-5))=0

We multiply parentheses

6t-(t-(t-5))+3-9=0



We calculate terms in parentheses: -(t-(t-5)), so:

t-(t-5)

We get rid of parentheses

t-t+5

We add all the numbers together, and all the variables

5

Back to the equation:

-(5)



We add all the numbers together, and all the variables

6t-11=0

We move all terms containing t to the left, all other terms to the right

6t=11

t=11/6

t=1+5/6

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