3(2t+1)=35

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Solution for 3(2t+1)=35 equation: 



3(2t+1)=35

We move all terms to the left:

3(2t+1)-(35)=0

We multiply parentheses

6t+3-35=0

We add all the numbers together, and all the variables

6t-32=0

We move all terms containing t to the left, all other terms to the right

6t=32

t=32/6

t=5+1/3

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