3(2t+2)=6(t+1)

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Solution for 3(2t+2)=6(t+1) equation: 



3(2t+2)=6(t+1)

We move all terms to the left:

3(2t+2)-(6(t+1))=0

We multiply parentheses

6t-(6(t+1))+6=0



We calculate terms in parentheses: -(6(t+1)), so:

6(t+1)

We multiply parentheses

6t+6

Back to the equation:

-(6t+6)



We get rid of parentheses

6t-6t-6+6=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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