3(2t-3)=2(3-2t)

Solution for 3(2t-3)=2(3-2t) equation:

3(2t-3)=2(3-2t)

We move all terms to the left:

3(2t-3)-(2(3-2t))=0

We add all the numbers together, and all the variables

3(2t-3)-(2(-2t+3))=0

We multiply parentheses

6t-(2(-2t+3))-9=0


We calculate terms in parentheses: -(2(-2t+3)), so:

2(-2t+3)

We multiply parentheses

-4t+6

Back to the equation:

-(-4t+6)


We get rid of parentheses

6t+4t-6-9=0

We add all the numbers together, and all the variables

10t-15=0

We move all terms containing t to the left, all other terms to the right

10t=15

t=15/10

t=1+1/2