3(2t-4)+20-6t=-3t-4

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Solution for 3(2t-4)+20-6t=-3t-4 equation: 



3(2t-4)+20-6t=-3t-4

We move all terms to the left:

3(2t-4)+20-6t-(-3t-4)=0

We add all the numbers together, and all the variables

-6t+3(2t-4)-(-3t-4)+20=0

We multiply parentheses

-6t+6t-(-3t-4)-12+20=0

We get rid of parentheses

-6t+6t+3t+4-12+20=0

We add all the numbers together, and all the variables

3t+12=0

We move all terms containing t to the left, all other terms to the right

3t=-12

t=-12/3

t=-4

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