3(2t-4)=4+t-1

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Solution for 3(2t-4)=4+t-1 equation: 



3(2t-4)=4+t-1

We move all terms to the left:

3(2t-4)-(4+t-1)=0

We add all the numbers together, and all the variables

3(2t-4)-(t+3)=0

We multiply parentheses

6t-(t+3)-12=0

We get rid of parentheses

6t-t-3-12=0

We add all the numbers together, and all the variables

5t-15=0

We move all terms containing t to the left, all other terms to the right

5t=15

t=15/5

t=3

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