3(2u+2)+8u+3=5(u-3)+3u

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Solution for 3(2u+2)+8u+3=5(u-3)+3u equation: 



3(2u+2)+8u+3=5(u-3)+3u

We move all terms to the left:

3(2u+2)+8u+3-(5(u-3)+3u)=0

We add all the numbers together, and all the variables

8u+3(2u+2)-(5(u-3)+3u)+3=0

We multiply parentheses

8u+6u-(5(u-3)+3u)+6+3=0



We calculate terms in parentheses: -(5(u-3)+3u), so:

5(u-3)+3u

We add all the numbers together, and all the variables

3u+5(u-3)

We multiply parentheses

3u+5u-15

We add all the numbers together, and all the variables

8u-15

Back to the equation:

-(8u-15)



We add all the numbers together, and all the variables

14u-(8u-15)+9=0

We get rid of parentheses

14u-8u+15+9=0

We add all the numbers together, and all the variables

6u+24=0

We move all terms containing u to the left, all other terms to the right

6u=-24

u=-24/6

u=-4

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