3(2u+3)=2(2u-3)

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Solution for 3(2u+3)=2(2u-3) equation: 



3(2u+3)=2(2u-3)

We move all terms to the left:

3(2u+3)-(2(2u-3))=0

We multiply parentheses

6u-(2(2u-3))+9=0



We calculate terms in parentheses: -(2(2u-3)), so:

2(2u-3)

We multiply parentheses

4u-6

Back to the equation:

-(4u-6)



We get rid of parentheses

6u-4u+6+9=0

We add all the numbers together, and all the variables

2u+15=0

We move all terms containing u to the left, all other terms to the right

2u=-15

u=-15/2

u=-7+1/2

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