3(2u-1)+5=6(u+1)

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Solution for 3(2u-1)+5=6(u+1) equation:


Simplifying
3(2u + -1) + 5 = 6(u + 1)

Reorder the terms:
3(-1 + 2u) + 5 = 6(u + 1)
(-1 * 3 + 2u * 3) + 5 = 6(u + 1)
(-3 + 6u) + 5 = 6(u + 1)

Reorder the terms:
-3 + 5 + 6u = 6(u + 1)

Combine like terms: -3 + 5 = 2
2 + 6u = 6(u + 1)

Reorder the terms:
2 + 6u = 6(1 + u)
2 + 6u = (1 * 6 + u * 6)
2 + 6u = (6 + 6u)

Add '-6u' to each side of the equation.
2 + 6u + -6u = 6 + 6u + -6u

Combine like terms: 6u + -6u = 0
2 + 0 = 6 + 6u + -6u
2 = 6 + 6u + -6u

Combine like terms: 6u + -6u = 0
2 = 6 + 0
2 = 6

Solving
2 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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