3(2u-2)-5=2(u+2)+5

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Solution for 3(2u-2)-5=2(u+2)+5 equation: 



3(2u-2)-5=2(u+2)+5

We move all terms to the left:

3(2u-2)-5-(2(u+2)+5)=0

We multiply parentheses

6u-(2(u+2)+5)-6-5=0



We calculate terms in parentheses: -(2(u+2)+5), so:

2(u+2)+5

We multiply parentheses

2u+4+5

We add all the numbers together, and all the variables

2u+9

Back to the equation:

-(2u+9)



We add all the numbers together, and all the variables

6u-(2u+9)-11=0

We get rid of parentheses

6u-2u-9-11=0

We add all the numbers together, and all the variables

4u-20=0

We move all terms containing u to the left, all other terms to the right

4u=20

u=20/4

u=5

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