3(2w+3)+4(w-5)=29

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Solution for 3(2w+3)+4(w-5)=29 equation: 



3(2w+3)+4(w-5)=29

We move all terms to the left:

3(2w+3)+4(w-5)-(29)=0

We multiply parentheses

6w+4w+9-20-29=0

We add all the numbers together, and all the variables

10w-40=0

We move all terms containing w to the left, all other terms to the right

10w=40

w=40/10

w=4

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