3(2w+3)+4(w-5)=29

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Solution for 3(2w+3)+4(w-5)=29 equation:



3(2w+3)+4(w-5)=29
We move all terms to the left:
3(2w+3)+4(w-5)-(29)=0
We multiply parentheses
6w+4w+9-20-29=0
We add all the numbers together, and all the variables
10w-40=0
We move all terms containing w to the left, all other terms to the right
10w=40
w=40/10
w=4

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