3(2w+3)=4(w-2)+20

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Solution for 3(2w+3)=4(w-2)+20 equation: 



3(2w+3)=4(w-2)+20

We move all terms to the left:

3(2w+3)-(4(w-2)+20)=0

We multiply parentheses

6w-(4(w-2)+20)+9=0



We calculate terms in parentheses: -(4(w-2)+20), so:

4(w-2)+20

We multiply parentheses

4w-8+20

We add all the numbers together, and all the variables

4w+12

Back to the equation:

-(4w+12)



We get rid of parentheses

6w-4w-12+9=0

We add all the numbers together, and all the variables

2w-3=0

We move all terms containing w to the left, all other terms to the right

2w=3

w=3/2

w=1+1/2

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