3(2w+5)=7(w-4)

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Solution for 3(2w+5)=7(w-4) equation: 



3(2w+5)=7(w-4)

We move all terms to the left:

3(2w+5)-(7(w-4))=0

We multiply parentheses

6w-(7(w-4))+15=0



We calculate terms in parentheses: -(7(w-4)), so:

7(w-4)

We multiply parentheses

7w-28

Back to the equation:

-(7w-28)



We get rid of parentheses

6w-7w+28+15=0

We add all the numbers together, and all the variables

-1w+43=0

We move all terms containing w to the left, all other terms to the right

-w=-43

w=-43/-1

w=+43

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