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3(2x)=4(x-5)
We move all terms to the left:
3(2x)-(4(x-5))=0
We calculate terms in parentheses: -(4(x-5)), so:We get rid of parentheses
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
32x-4x+20=0
We add all the numbers together, and all the variables
28x+20=0
We move all terms containing x to the left, all other terms to the right
28x=-20
x=-20/28
x=-5/7
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