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3(2x+-14)+x=15-x(-9x+-5)
We move all terms to the left:
3(2x+-14)+x-(15-x(-9x+-5))=0
We add all the numbers together, and all the variables
3(2x-14)+x-(15-x(-9x-5))=0
We add all the numbers together, and all the variables
x+3(2x-14)-(15-x(-9x-5))=0
We multiply parentheses
x+6x-(15-x(-9x-5))-42=0
We calculate terms in parentheses: -(15-x(-9x-5)), so:We add all the numbers together, and all the variables
15-x(-9x-5)
determiningTheFunctionDomain -x(-9x-5)+15
We multiply parentheses
9x^2+5x+15
Back to the equation:
-(9x^2+5x+15)
7x-(9x^2+5x+15)-42=0
We get rid of parentheses
-9x^2+7x-5x-15-42=0
We add all the numbers together, and all the variables
-9x^2+2x-57=0
a = -9; b = 2; c = -57;
Δ = b2-4ac
Δ = 22-4·(-9)·(-57)
Δ = -2048
Delta is less than zero, so there is no solution for the equation
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