3(2x+-5)=6(x+-4)+9

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Solution for 3(2x+-5)=6(x+-4)+9 equation:



3(2x+-5)=6(x+-4)+9
We move all terms to the left:
3(2x+-5)-(6(x+-4)+9)=0
We add all the numbers together, and all the variables
3(2x-5)-(6(x-4)+9)=0
We multiply parentheses
6x-(6(x-4)+9)-15=0
We calculate terms in parentheses: -(6(x-4)+9), so:
6(x-4)+9
We multiply parentheses
6x-24+9
We add all the numbers together, and all the variables
6x-15
Back to the equation:
-(6x-15)
We get rid of parentheses
6x-6x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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