3(2x+1)+(4x+2)=35

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Solution for 3(2x+1)+(4x+2)=35 equation: 



3(2x+1)+(4x+2)=35

We move all terms to the left:

3(2x+1)+(4x+2)-(35)=0

We multiply parentheses

6x+(4x+2)+3-35=0

We get rid of parentheses

6x+4x+2+3-35=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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