3(2x+1)+2(3x+2)=35

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Solution for 3(2x+1)+2(3x+2)=35 equation: 



3(2x+1)+2(3x+2)=35

We move all terms to the left:

3(2x+1)+2(3x+2)-(35)=0

We multiply parentheses

6x+6x+3+4-35=0

We add all the numbers together, and all the variables

12x-28=0

We move all terms containing x to the left, all other terms to the right

12x=28

x=28/12

x=2+1/3

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