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3(2x+1)+2x=-x+3(3x+1)
We move all terms to the left:
3(2x+1)+2x-(-x+3(3x+1))=0
We add all the numbers together, and all the variables
2x+3(2x+1)-(-x+3(3x+1))=0
We multiply parentheses
2x+6x-(-x+3(3x+1))+3=0
We calculate terms in parentheses: -(-x+3(3x+1)), so:We add all the numbers together, and all the variables
-x+3(3x+1)
We add all the numbers together, and all the variables
-1x+3(3x+1)
We multiply parentheses
-1x+9x+3
We add all the numbers together, and all the variables
8x+3
Back to the equation:
-(8x+3)
8x-(8x+3)+3=0
We get rid of parentheses
8x-8x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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