3(2x+1)+2x=8x+3(-3x)

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Solution for 3(2x+1)+2x=8x+3(-3x) equation: 



3(2x+1)+2x=8x+3(-3x)

We move all terms to the left:

3(2x+1)+2x-(8x+3(-3x))=0

We add all the numbers together, and all the variables

2x+3(2x+1)-(8x+3(-3x))=0

We multiply parentheses

2x+6x-(8x+3(-3x))+3=0



We calculate terms in parentheses: -(8x+3(-3x)), so:

8x+3(-3x)

We multiply parentheses

8x-9x

We add all the numbers together, and all the variables

-x

Back to the equation:

-(-x)



We add all the numbers together, and all the variables

2x+6x-(-1x)+3=0

We add all the numbers together, and all the variables

8x-(-1x)+3=0

We get rid of parentheses

8x+1x+3=0

We add all the numbers together, and all the variables

9x+3=0

We move all terms containing x to the left, all other terms to the right

9x=-3

x=-3/9

x=-1/3

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