3(2x+1)+3=9(x+2)+9-3x

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Solution for 3(2x+1)+3=9(x+2)+9-3x equation:



3(2x+1)+3=9(x+2)+9-3x
We move all terms to the left:
3(2x+1)+3-(9(x+2)+9-3x)=0
We multiply parentheses
6x-(9(x+2)+9-3x)+3+3=0
We calculate terms in parentheses: -(9(x+2)+9-3x), so:
9(x+2)+9-3x
determiningTheFunctionDomain 9(x+2)-3x+9
We add all the numbers together, and all the variables
-3x+9(x+2)+9
We multiply parentheses
-3x+9x+18+9
We add all the numbers together, and all the variables
6x+27
Back to the equation:
-(6x+27)
We add all the numbers together, and all the variables
6x-(6x+27)+6=0
We get rid of parentheses
6x-6x-27+6=0
We add all the numbers together, and all the variables
-21!=0
There is no solution for this equation

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