3(2x+1)+3=9(x+2)+9-3x

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Solution for 3(2x+1)+3=9(x+2)+9-3x equation: 



3(2x+1)+3=9(x+2)+9-3x

We move all terms to the left:

3(2x+1)+3-(9(x+2)+9-3x)=0

We multiply parentheses

6x-(9(x+2)+9-3x)+3+3=0



We calculate terms in parentheses: -(9(x+2)+9-3x), so:

9(x+2)+9-3x

determiningTheFunctionDomain
9(x+2)-3x+9

We add all the numbers together, and all the variables

-3x+9(x+2)+9

We multiply parentheses

-3x+9x+18+9

We add all the numbers together, and all the variables

6x+27

Back to the equation:

-(6x+27)



We add all the numbers together, and all the variables

6x-(6x+27)+6=0

We get rid of parentheses

6x-6x-27+6=0

We add all the numbers together, and all the variables

-21!=0

There is no solution for this equation

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