3(2x+1)+4x=33

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Solution for 3(2x+1)+4x=33 equation: 



3(2x+1)+4x=33

We move all terms to the left:

3(2x+1)+4x-(33)=0

We add all the numbers together, and all the variables

4x+3(2x+1)-33=0

We multiply parentheses

4x+6x+3-33=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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