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3(2x+1)+5x=2(5x+3)-2
We move all terms to the left:
3(2x+1)+5x-(2(5x+3)-2)=0
We add all the numbers together, and all the variables
5x+3(2x+1)-(2(5x+3)-2)=0
We multiply parentheses
5x+6x-(2(5x+3)-2)+3=0
We calculate terms in parentheses: -(2(5x+3)-2), so:We add all the numbers together, and all the variables
2(5x+3)-2
We multiply parentheses
10x+6-2
We add all the numbers together, and all the variables
10x+4
Back to the equation:
-(10x+4)
11x-(10x+4)+3=0
We get rid of parentheses
11x-10x-4+3=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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