3(2x+1)+7=6x-3-2(2-4x)

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Solution for 3(2x+1)+7=6x-3-2(2-4x) equation: 



3(2x+1)+7=6x-3-2(2-4x)

We move all terms to the left:

3(2x+1)+7-(6x-3-2(2-4x))=0

We add all the numbers together, and all the variables

3(2x+1)-(6x-3-2(-4x+2))+7=0

We multiply parentheses

6x-(6x-3-2(-4x+2))+3+7=0



We calculate terms in parentheses: -(6x-3-2(-4x+2)), so:

6x-3-2(-4x+2)

determiningTheFunctionDomain
6x-2(-4x+2)-3

We multiply parentheses

6x+8x-4-3

We add all the numbers together, and all the variables

14x-7

Back to the equation:

-(14x-7)



We add all the numbers together, and all the variables

6x-(14x-7)+10=0

We get rid of parentheses

6x-14x+7+10=0

We add all the numbers together, and all the variables

-8x+17=0

We move all terms containing x to the left, all other terms to the right

-8x=-17

x=-17/-8

x=2+1/8

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