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3(2x+1)+x=139
We move all terms to the left:
3(2x+1)+x-(139)=0
We add all the numbers together, and all the variables
x+3(2x+1)-139=0
We multiply parentheses
x+6x+3-139=0
We add all the numbers together, and all the variables
7x-136=0
We move all terms containing x to the left, all other terms to the right
7x=136
x=136/7
x=19+3/7
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