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3(2x+1)+x=7(x+2)
We move all terms to the left:
3(2x+1)+x-(7(x+2))=0
We add all the numbers together, and all the variables
x+3(2x+1)-(7(x+2))=0
We multiply parentheses
x+6x-(7(x+2))+3=0
We calculate terms in parentheses: -(7(x+2)), so:We add all the numbers together, and all the variables
7(x+2)
We multiply parentheses
7x+14
Back to the equation:
-(7x+14)
7x-(7x+14)+3=0
We get rid of parentheses
7x-7x-14+3=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation
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