3(2x+1)-(x+2)=(7x+1)-4(x-3)

Solution for 3(2x+1)-(x+2)=(7x+1)-4(x-3) equation:

3(2x+1)-(x+2)=(7x+1)-4(x-3)

We move all terms to the left:

3(2x+1)-(x+2)-((7x+1)-4(x-3))=0

We multiply parentheses

6x-(x+2)-((7x+1)-4(x-3))+3=0

We get rid of parentheses

6x-x-((7x+1)-4(x-3))-2+3=0


We calculate terms in parentheses: -((7x+1)-4(x-3)), so:

(7x+1)-4(x-3)

We multiply parentheses

(7x+1)-4x+12

We get rid of parentheses

7x-4x+1+12

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)


We add all the numbers together, and all the variables

5x-(3x+13)+1=0

We get rid of parentheses

5x-3x-13+1=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6