3(2x+1)-(x+2)=3(3x+4)

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Solution for 3(2x+1)-(x+2)=3(3x+4) equation: 



3(2x+1)-(x+2)=3(3x+4)

We move all terms to the left:

3(2x+1)-(x+2)-(3(3x+4))=0

We multiply parentheses

6x-(x+2)-(3(3x+4))+3=0

We get rid of parentheses

6x-x-(3(3x+4))-2+3=0



We calculate terms in parentheses: -(3(3x+4)), so:

3(3x+4)

We multiply parentheses

9x+12

Back to the equation:

-(9x+12)



We add all the numbers together, and all the variables

5x-(9x+12)+1=0

We get rid of parentheses

5x-9x-12+1=0

We add all the numbers together, and all the variables

-4x-11=0

We move all terms containing x to the left, all other terms to the right

-4x=11

x=11/-4

x=-2+3/4

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