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3(2x+1)-2(3x+5)=12x
We move all terms to the left:
3(2x+1)-2(3x+5)-(12x)=0
We add all the numbers together, and all the variables
-12x+3(2x+1)-2(3x+5)=0
We multiply parentheses
-12x+6x-6x+3-10=0
We add all the numbers together, and all the variables
-12x-7=0
We move all terms containing x to the left, all other terms to the right
-12x=7
x=7/-12
x=-7/12
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