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3(2x+1)-2(x-5)-5(5-2x)=6
We move all terms to the left:
3(2x+1)-2(x-5)-5(5-2x)-(6)=0
We add all the numbers together, and all the variables
3(2x+1)-2(x-5)-5(-2x+5)-6=0
We multiply parentheses
6x-2x+10x+3+10-25-6=0
We add all the numbers together, and all the variables
14x-18=0
We move all terms containing x to the left, all other terms to the right
14x=18
x=18/14
x=1+2/7
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