3(2x+1)-4(2-x)=4x+5(2x-2)

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Solution for 3(2x+1)-4(2-x)=4x+5(2x-2) equation: 



3(2x+1)-4(2-x)=4x+5(2x-2)

We move all terms to the left:

3(2x+1)-4(2-x)-(4x+5(2x-2))=0

We add all the numbers together, and all the variables

3(2x+1)-4(-1x+2)-(4x+5(2x-2))=0

We multiply parentheses

6x+4x-(4x+5(2x-2))+3-8=0



We calculate terms in parentheses: -(4x+5(2x-2)), so:

4x+5(2x-2)

We multiply parentheses

4x+10x-10

We add all the numbers together, and all the variables

14x-10

Back to the equation:

-(14x-10)



We add all the numbers together, and all the variables

10x-(14x-10)-5=0

We get rid of parentheses

10x-14x+10-5=0

We add all the numbers together, and all the variables

-4x+5=0

We move all terms containing x to the left, all other terms to the right

-4x=-5

x=-5/-4

x=1+1/4

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