3(2x+1)-5(3x+2)=-4(2x+1)-(x+3)

Solution for 3(2x+1)-5(3x+2)=-4(2x+1)-(x+3) equation:

3(2x+1)-5(3x+2)=-4(2x+1)-(x+3)

We move all terms to the left:

3(2x+1)-5(3x+2)-(-4(2x+1)-(x+3))=0

We multiply parentheses

6x-15x-(-4(2x+1)-(x+3))+3-10=0


We calculate terms in parentheses: -(-4(2x+1)-(x+3)), so:

-4(2x+1)-(x+3)

We multiply parentheses

-8x-(x+3)-4

We get rid of parentheses

-8x-x-3-4

We add all the numbers together, and all the variables

-9x-7

Back to the equation:

-(-9x-7)


We add all the numbers together, and all the variables

-9x-(-9x-7)-7=0

We get rid of parentheses

-9x+9x+7-7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0