3(2x+1)-5=6(x-1)+4

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Solution for 3(2x+1)-5=6(x-1)+4 equation:


Simplifying
3(2x + 1) + -5 = 6(x + -1) + 4

Reorder the terms:
3(1 + 2x) + -5 = 6(x + -1) + 4
(1 * 3 + 2x * 3) + -5 = 6(x + -1) + 4
(3 + 6x) + -5 = 6(x + -1) + 4

Reorder the terms:
3 + -5 + 6x = 6(x + -1) + 4

Combine like terms: 3 + -5 = -2
-2 + 6x = 6(x + -1) + 4

Reorder the terms:
-2 + 6x = 6(-1 + x) + 4
-2 + 6x = (-1 * 6 + x * 6) + 4
-2 + 6x = (-6 + 6x) + 4

Reorder the terms:
-2 + 6x = -6 + 4 + 6x

Combine like terms: -6 + 4 = -2
-2 + 6x = -2 + 6x

Add '2' to each side of the equation.
-2 + 2 + 6x = -2 + 2 + 6x

Combine like terms: -2 + 2 = 0
0 + 6x = -2 + 2 + 6x
6x = -2 + 2 + 6x

Combine like terms: -2 + 2 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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