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3(2x+1)-8=5-3(3x+2)+6x
We move all terms to the left:
3(2x+1)-8-(5-3(3x+2)+6x)=0
We multiply parentheses
6x-(5-3(3x+2)+6x)+3-8=0
We calculate terms in parentheses: -(5-3(3x+2)+6x), so:We add all the numbers together, and all the variables
5-3(3x+2)+6x
determiningTheFunctionDomain -3(3x+2)+6x+5
We add all the numbers together, and all the variables
6x-3(3x+2)+5
We multiply parentheses
6x-9x-6+5
We add all the numbers together, and all the variables
-3x-1
Back to the equation:
-(-3x-1)
6x-(-3x-1)-5=0
We get rid of parentheses
6x+3x+1-5=0
We add all the numbers together, and all the variables
9x-4=0
We move all terms containing x to the left, all other terms to the right
9x=4
x=4/9
x=4/9
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