3(2x+1)/2=4(x-2)/5+x

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Solution for 3(2x+1)/2=4(x-2)/5+x equation: 


x in (-oo:+oo)

(3*(2*x+1))/2 = (4*(x-2))/5+x // - (4*(x-2))/5+x

(3*(2*x+1))/2-((4*(x-2))/5)-x = 0

(3*(2*x+1))/2+(-4/5)*(x-2)-x = 0

(3*(2*x+1))/2-4/5*(x-2)-x = 0

(3*(2*x+1))/2+(-4/5*2*(x-2))/2+(2*(-x))/2 = 0

3*(2*x+1)-4/5*2*(x-2)+2*(-x) = 0

22/5*x-2*x+31/5 = 0

12/5*x+31/5 = 0

(12/5*x+31/5)/2 = 0

(12/5*x+31/5)/2 = 0 // * 2

12/5*x+31/5 = 0

12/5*x+31/5 = 0 // - 31/5

12/5*x = -31/5 // : 12/5

x = -31/5/12/5

x = -31/12

x = -31/12

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