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3(2x+1)/5=3
We move all terms to the left:
3(2x+1)/5-(3)=0
We multiply all the terms by the denominator
3(2x+1)-3*5=0
We add all the numbers together, and all the variables
3(2x+1)-15=0
We multiply parentheses
6x+3-15=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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