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3(2x+1)/5=9
We move all terms to the left:
3(2x+1)/5-(9)=0
We multiply all the terms by the denominator
3(2x+1)-9*5=0
We add all the numbers together, and all the variables
3(2x+1)-45=0
We multiply parentheses
6x+3-45=0
We add all the numbers together, and all the variables
6x-42=0
We move all terms containing x to the left, all other terms to the right
6x=42
x=42/6
x=7
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