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3(2x+1)7x=11
We move all terms to the left:
3(2x+1)7x-(11)=0
We multiply parentheses
42x^2+21x-11=0
a = 42; b = 21; c = -11;
Δ = b2-4ac
Δ = 212-4·42·(-11)
Δ = 2289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{2289}}{2*42}=\frac{-21-\sqrt{2289}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{2289}}{2*42}=\frac{-21+\sqrt{2289}}{84} $
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