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3(2x+1)=(2x+11)
We move all terms to the left:
3(2x+1)-((2x+11))=0
We multiply parentheses
6x-((2x+11))+3=0
We calculate terms in parentheses: -((2x+11)), so:We get rid of parentheses
(2x+11)
We get rid of parentheses
2x+11
Back to the equation:
-(2x+11)
6x-2x-11+3=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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