3(2x+1)=(8x+1)-1

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Solution for 3(2x+1)=(8x+1)-1 equation: 



3(2x+1)=(8x+1)-1

We move all terms to the left:

3(2x+1)-((8x+1)-1)=0

We multiply parentheses

6x-((8x+1)-1)+3=0



We calculate terms in parentheses: -((8x+1)-1), so:

(8x+1)-1

We get rid of parentheses

8x+1-1

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-2x+3=0

We move all terms containing x to the left, all other terms to the right

-2x=-3

x=-3/-2

x=1+1/2

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