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3(2x+1)=+2(x+4)
We move all terms to the left:
3(2x+1)-(+2(x+4))=0
We multiply parentheses
6x-(+2(x+4))+3=0
We calculate terms in parentheses: -(+2(x+4)), so:We get rid of parentheses
+2(x+4)
determiningTheFunctionDomain 2(x+4)
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
6x-2x-8+3=0
We add all the numbers together, and all the variables
4x-5=0
We move all terms containing x to the left, all other terms to the right
4x=5
x=5/4
x=1+1/4
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