3(2x+1)=17-2(x-1)=

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Solution for 3(2x+1)=17-2(x-1)= equation: 



3(2x+1)=17-2(x-1)=

We move all terms to the left:

3(2x+1)-(17-2(x-1))=0

We multiply parentheses

6x-(17-2(x-1))+3=0



We calculate terms in parentheses: -(17-2(x-1)), so:

17-2(x-1)

determiningTheFunctionDomain
-2(x-1)+17

We multiply parentheses

-2x+2+17

We add all the numbers together, and all the variables

-2x+19

Back to the equation:

-(-2x+19)



We get rid of parentheses

6x+2x-19+3=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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